Hi guys!!

Today I took my calc test and I'm curious to see if I did the last one right.

Set up the integral or integrals to find the area

**shared** by the polar curves given by:

$\displaystyle r=\sin2\theta $

$\displaystyle r=\frac{1}{2}$

$\displaystyle 0\leq\theta\leq\frac{\pi}{2}$

I found the points of intersection:

$\displaystyle \sin2\theta=\frac{1}{2}$

$\displaystyle \theta=\frac{\pi}{12},\frac{5\pi}{12}$

From there I can't remember exactly what I did, but if someone could just set up the integrals, I'm sure I can remember if that's what I did when I see it. I know there are probably a few different ways, but I would appreciate any input! I can't wait a week because I've been stressing out about this problem! And, if I got it wrong, I'd rather cry at home...(I'm kidding!...well, not really....