1. ## antiderivative?

I know the antiderivative of sin is -cos. But what is the antiderivative of -cos? Is it -sin?

It's for this problem (not a test question, just homework):

[IMG]file:///C:/DOCUME%7E1/COMPAQ%7E1/LOCALS%7E1/Temp/moz-screenshot-2.jpg[/IMG]Given and and . Find ?

I got that the first derivative is (-16)(-cos(4x)) -20
but for f(x) i am not sure what the antiderivative of -cosx is.

Thanks!
[IMG]file:///C:/DOCUME%7E1/COMPAQ%7E1/LOCALS%7E1/Temp/moz-screenshot.jpg[/IMG][IMG]file:///C:/DOCUME%7E1/COMPAQ%7E1/LOCALS%7E1/Temp/moz-screenshot-1.jpg[/IMG]

2. Originally Posted by tennisgirl
I know the antiderivative of sin is -cos. But what is the antiderivative of -cos? Is it -sin?

It's for this problem (not a test question, just homework):

[IMG]file:///C:/DOCUME%7E1/COMPAQ%7E1/LOCALS%7E1/Temp/moz-screenshot-2.jpg[/IMG]Given and and . Find ?

I got that the first derivative is (-16)(-cos(4x)) -20
but for f(x) i am not sure what the antiderivative of -cosx is.

Thanks!
[IMG]file:///C:/DOCUME%7E1/COMPAQ%7E1/LOCALS%7E1/Temp/moz-screenshot.jpg[/IMG][IMG]file:///C:/DOCUME%7E1/COMPAQ%7E1/LOCALS%7E1/Temp/moz-screenshot-1.jpg[/IMG]
I am sure you know that $\displaystyle \int{cos(x)dx}=sin(x)$...well $\displaystyle \int{-cos(x)dx}=-\int{cos(x)dx}=-sin(x)+C$