$\displaystyle y\prime+\frac{2}{t}y=\frac{arctant}{t^{2}}$

here they want the y(t) equation

so first what I tried doing was integrating t/2

so I got the factor was $\displaystyle e^{lnt^{2}}$ which equals to 2

so now I have to integrate

$\displaystyle \frac{d}{dt}2y=2\frac{arctant}{t^2}$

which in the end would turn out to be

$\displaystyle y(t)=\frac{tarctant-0.5ln(t^{2}+1)}{t^{2}}+C/2$

so I can't help but feel I did something wrong???