Write an equation of the plane with normal vector passing through the point in scalar form:
-6x+(-7)y+(-3)z+180
This answer is incorrect. I found d to be 60, but I can't get it right - please help!
If $\displaystyle n = \left\langle { - 6, - 7, - 3} \right\rangle $ is the normal the we can use any multiple, so let $\displaystyle n = \left\langle { 6, 7, 3} \right\rangle$.
The general plane is $\displaystyle 6x + 7y + 3z + d = 0$.
Now substitute the point to find d: $\displaystyle 6(2) + 7( - 9) + 3( - 3) + d = 0 \Rightarrow \quad d = 60$.
Dee, May I ask: "Do you have an instructor and/or a textbook?