Find the area of the parallelogram with vertices at and
Area = ?
I've found the base vector multiplied by the sidw vector to be , or 50.1996. I need to find the angle between these two vectors.
to find the angle between two vectors use the dot product
$\displaystyle v_1=3 \vec i -5 \vec j,v_2=-3 \vec i -11\vec j$
$\displaystyle v_1 \cdot v_2=|v_1||v_2|\cos(\theta)$
$\displaystyle -9+55=\sqrt{34} \cdot \sqrt{130} \cos(\theta)$
$\displaystyle \cos(\theta)=\frac{46}{\sqrt{4420}}$
Check my work as this was done while I was riding a bus without a calculator, but the theory is correct.
good luck.