Originally Posted by

**larson** Determine whether the series converges or diverges. If the series converges, find its limit. Justify your answers.

$\displaystyle \sum_{j=2}^{\infty} \frac{3^j}{4^{j+1}}$

So first I did this, although I'm not sure if I'm going in the right direction, although I believe I am...

= $\displaystyle \frac {3^2}{4^3} (1 + \frac {3}{4} + \frac {3^2}{4^2} + \frac {3^3}{4^3} ...)$ then I can't figure out what the stuff inside the parenthesis equals out to be, then I could figure out the answer.