Hello,
Use the chain rule :
You have to find the derivative for ln((t^2 + 1)/(t^2 - 1))=ln(u(t))
Its derivative will be
So let's calculate u'(t).
This will be calculated with the quotient rule :
Here, and
Hence
I have the equation:
s(t) = ln((t^2 + 1)/(t^2 - 1)) + 6lnt
on the interval 1.1 < t < 10.
How do I find the derivative of this? If someone could show me step-by-step, I'd really appreciate it as I'm having troubles with this one.
Thanks!
Maximum and minimum values are points where the derivative is null.
Make the fractions in the derivative have the same denominator, then look the values of x for which the numerator is null.
To know if it's a maximum or a minimum, you can do a table of signs, or study the second derivative (which can be tricky)
calculus or calculation ?