I have the equation:

s(t) = ln((t^2 + 1)/(t^2 - 1)) + 6lnt

on the interval 1.1 < t < 10.

How do I find the derivative of this? If someone could show me step-by-step, I'd really appreciate it as I'm having troubles with this one.

Thanks!

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- Apr 20th 2008, 01:16 PMJeavusDerivative of a Natural LogI have the equation:

s(t) = ln((t^2 + 1)/(t^2 - 1)) + 6lnt

on the interval 1.1 < t < 10.

How do I find the derivative of this? If someone could show me step-by-step, I'd really appreciate it as I'm having troubles with this one.

Thanks!

- Apr 20th 2008, 01:26 PMMoo
Hello,

Use the chain rule :

You have to find the derivative for ln((t^2 + 1)/(t^2 - 1))=ln(u(t))

Its derivative will be

So let's calculate u'(t).

This will be calculated with the quotient rule :

Here, and

Hence

- Apr 20th 2008, 01:35 PMflyingsquirrel
Hi

Otherwise, you can also split the log into two parts :

and then differentiate each term:

- Apr 20th 2008, 01:36 PMMoo
I was obsessed with the calculus... :D

- Apr 20th 2008, 01:40 PMJeavus
Thanks both of you.

Now, from that derivative, how do I find the maximum and minimum values for the function?

:) - Apr 20th 2008, 01:44 PMJhevon
- Apr 20th 2008, 01:44 PMMoo
Maximum and minimum values are points where the derivative is null.

Make the fractions in the derivative have the same denominator, then look the values of x for which the numerator is null.

To know if it's a maximum or a minimum, you can do a table of signs, or study the second derivative (which can be tricky) - Apr 20th 2008, 01:47 PMflyingsquirrel
calculus or calculation ? :D

- Apr 20th 2008, 01:49 PMJeavusOkay, I'm trying to solve for the t value but I can't.

s'(t) = (6t^4 - 4t^2 - 6)/(t)(t^2 + 1)(t^2 - 1)

Where do I go from here?

- Apr 20th 2008, 01:50 PMMoo
- Apr 20th 2008, 01:51 PMJhevon
- Apr 20th 2008, 01:52 PMMoo