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Thread: problem when using cauchy integral formula

  1. April 20th 2008, 11:38 AM #1
    prescott2006
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    problem when using cauchy integral formula

    who know how to convert z/(z^2+9) to z/(z+3i)/(z-3i)?i really do not have any idea how the book convert it.
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  2. April 20th 2008, 12:19 PM #2
    topsquark
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    Quote Originally Posted by prescott2006 View Post
    who know how to convert z/(z^2+9) to z/(z+3i)/(z-3i)?i really do not have any idea how the book convert it.
    If you don't see it, do it backwards and FOIL it out. Otherwise:
    x^2 + 9 = x^2 - (-9) = (x + \sqrt{-9})(x - \sqrt{-9}) = (x + 3i)(x - 3i)

    -Dan
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