1. ## surface integral

Find the surface area of the portion of the sphere x^2+y^2+z^2=25 that is above the region in the first quadrant bounded by the graphs of x=0, y=0, 4x^2+y^2=25.Any idea?

Does polar coordinate can be use when the shape is ellipse?

2. Originally Posted by prescott2006
actually i was stuck in integrate 5/sqrt(25-x^2-y^2) dA. It seem can be integrate using polar coordinate.but it is an ellipse so i think it cant be.but if do not use polar coordinate the integration is too tedious.So any suggestion?
So what is the question? Are you

1. integrating 5/sqrt(25-x^2-y^2) over the area of the portion of the sphere x^2+y^2+z^2=25 that is above the region in the first quadrant bounded by the graphs of x=0, y=0, 4x^2+y^2=25?

Or are you just wanting to

2. find the surface area of the portion of the sphere x^2+y^2+z^2=25 that is above the region in the first quadrant bounded by the graphs of x=0, y=0, 4x^2+y^2=25?