Oh right, thanks
and for the 2nd one i get..
y^-2 dy/dx = y/x
integrate y^1/2 /y dy = integrate 1/x dx
integrate y^-1/2 dy = integrate x^-1 dx
= 1/2 y^1/2 = x
i get confused with the last bit, you add 1 to the power and divide by the new power dont you?
thanks a lot so far!