Show that converges. A little bit puzzled here.
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Originally Posted by larson Show that converges. A little bit puzzled here. It is defined on so just do it therefore it converges
Originally Posted by Mathstud28 It is defined on so just do it therefore it converges crap... i wrote the problem wrong... it's ... show that it CONVERGES.
Last edited by larson; April 19th 2008 at 06:29 PM.
Originally Posted by larson Show that converges. A little bit puzzled here. This seems a little weird. Cosine is continous for all real numbers and has an antiderivative. This type of question is usuall asked when you have a vertical asymptote or somthing. It would converge to Maybe I missed the point?
Originally Posted by larson crap... i wrote the problem wrong... it's ... ahh the plot thickens express cosine as its power series so then integrate term by term and evaluate. This will converges by the AST. Good luck.
Originally Posted by larson crap... i wrote the problem wrong... it's ... That integral diverges, note that as
Originally Posted by TheEmptySet ahh the plot thickens express cosine as its power series so then integrate term by term and evaluate. This will converges by the AST. Good luck. I'm a little confused here by this... is that just general knowledge?
Originally Posted by larson crap... i wrote the problem wrong... it's ... The integral diverges?
express cosine as its power series so then integrate term by term and evaluate and the sum diverges.
Originally Posted by larson I'm a little confused here by this... is that just general knowledge? I used the wrong power series. sorry
Originally Posted by Mathstud28 The integral diverges? I'm so sorry, I'm making this much much more confusing that what I intended it to be. It converges...
Originally Posted by larson I'm so sorry, I'm making this much much more confusing that what I intended it to be. It converges... This integral diverges?
Originally Posted by Mathstud28 This integral diverges? Sorry, I wrote it down wrong. The problem is... explain how this CONVERGES.
Originally Posted by larson I'm so sorry, I'm making this much much more confusing that what I intended it to be. It converges... Maybe it is or (both converge since as )
Originally Posted by larson Sorry, I wrote it down wrong. The problem is... explain how this CONVERGES. ok which diverges from 0 to 1...it still doesn't converge
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