Does this series convergence?: $\displaystyle \sum _{n=1}^\infty \frac{\arcsin \left(\frac{1}{n^2}\right)}{\arctan \left(\frac{1}{n^2}\right)}\$
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$\displaystyle \lim _{n \to \infty } \frac{\arcsin \left(\frac{1}{n^2}\right)}{\arctan \left(\frac{1}{n^2}\right)}=?\$
Originally Posted by Plato $\displaystyle \lim _{n \to \infty } \frac{\arcsin \left(\frac{1}{n^2}\right)}{\arctan \left(\frac{1}{n^2}\right)}=?\$ Thank You!.... I completely by passed the simplest test of them all!
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