Can't seem to figure it out. $\displaystyle \frac{d^{2}z}{dx^2}.......... z=arctan(\frac{y}{x}) $ Thanks. I did not know how to make a tan inverse in Latex.
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Originally Posted by Gotovina7 Can't seem to figure it out. $\displaystyle \frac{d^{2}z}{dx^2}.......... z=arctan(\frac{y}{x}) $ Thanks. I did not know how to make a tan inverse in Latex. p.s the code is tan^{-1} $\displaystyle \frac{\partial z}{\partial x}=\frac{1}{1+\left( \frac{y}{x} \right)^2}\cdot \left( -\frac{y}{x^2}\right)=\frac{-y}{x^2+y^2}$ taking one more gives $\displaystyle \frac{\partial ^2 z}{\partial x^2}=\frac{2xy}{(x^2+y^2)^2}$
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