# stationary point of multivariable function

• April 18th 2008, 11:33 AM
tak
stationary point of multivariable function
A three-dimensional surface is given by the function
f= x(3-x^2-y^2)

1)show that the points (1,0) and (-1) are stationary points of the function

2) Determine the nature(maximum or minimum of the stationary points at (1,0)
and (-1,0)

3) Determine the location of the other two stationary points of the function
• April 18th 2008, 12:34 PM
heathrowjohnny
Set $\nabla f = 0$ and solve.
• April 19th 2008, 12:57 AM
tak
Can't seems to get the stationary point
i got y=0 and x=-1. how to get the other point?
• April 19th 2008, 02:01 AM
tak
max min point
(-1,0) min point? correct?
(1,0) max point correct?
• April 21st 2008, 09:04 AM
tak
solve
I manage to solve it....
fx=fy=0