Hiyah, how do I work out the integral of cot^2(x)dx?
I worked out that the differential cotxdx is -csc^2(x) and apparently this is supposed to help.
I've tried all sorts of perverted methods but they're going nowhere. Any clues?
Cheers.
Hiyah, how do I work out the integral of cot^2(x)dx?
I worked out that the differential cotxdx is -csc^2(x) and apparently this is supposed to help.
I've tried all sorts of perverted methods but they're going nowhere. Any clues?
Cheers.
Hello, Xei!
Recall that: .$\displaystyle \csc^2\!\theta \;=\;\cot^2\!\theta+1 \quad\Rightarrow\quad \cot^2\!\theta \;=\;\csc^2\!\theta - 1$$\displaystyle \int \cot^2\!x\,dx$
Then we have: .$\displaystyle \int \cot^2\!x\,dx \;=\;\int(\csc^2\!x - 1)\,dx \;=\;\int\csc^2\!x\,dx - \int\,dx$
Got it?