we have and I am to find the part of the surface that lies above a triangle with vertices at (0,0),(0,1),(2,1).
So far: , so the integral looks ugly...
we have and I am to find the part of the surface that lies above a triangle with vertices at (0,0),(0,1),(2,1).
So far: , so the integral looks ugly...
Have you sketched the region of integration in the xy-plane?
Your integral is .
Life is much easier if you reverse the order of integration: