we have and I am to find the part of the surface that lies above a triangle with vertices at (0,0),(0,1),(2,1).

So far:

, so the integral looks ugly...

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- Apr 17th 2008, 07:12 PMapw235@nyu.eduAnother Surface Area question
we have and I am to find the part of the surface that lies above a triangle with vertices at (0,0),(0,1),(2,1).

So far:

, so the integral looks ugly... - Apr 18th 2008, 05:47 AMapw235@nyu.edu
bump

- Apr 18th 2008, 06:04 AMmr fantastic