ok so where did I go wrong.. ...

so I first did this ...so then I seperated it to get

Then using substitution by power series I got

...then I went

...could someone point out my mistake...thanks

Results 1 to 10 of 10

- April 16th 2008, 04:17 PM #1
## Ingtegral

ok so where did I go wrong.. ...

so I first did this ...so then I seperated it to get

Then using substitution by power series I got

...then I went

...could someone point out my mistake...thanks

- April 16th 2008, 05:18 PM #2

- April 16th 2008, 11:35 PM #3

- April 17th 2008, 02:36 AM #4

- April 17th 2008, 06:50 AM #5

- April 17th 2008, 07:24 AM #6

- April 17th 2008, 07:29 AM #7

- April 17th 2008, 07:36 AM #8
I argued it too ^_^ (didn't get the points back, though)

Best I can figure is that the function applies to the funciton directly to it's right, In this case, that means f(x) = x^2, and g(x) = mx^2 so this is cos f(g(x))

This may not be what the problem is, IDK, but since the OP doesn't include the answer, I figured it could be, since I've experienced similar frustration in the past.

- April 17th 2008, 11:49 AM #9

- April 17th 2008, 12:10 PM #10