# Math Help - Help with another limit

1. ## Help with another limit

I am completley stuck on this limit and have no clue what to do here, I am trying to use the ratio test to see if it converges or diverges. The limit as k goes to infinity of (k!4^k)/((k+1)!4^(k+1)). Can anybody help me figure out what to do here?

Thank You

2. Hello,

$(n+1)!=1*2* \dots *n*(n+1)$

$n!=1*2* \dots *n$

So $(n+1)!=(n+1)*n!$

-> How can you simplify $\frac{k!}{(k+1)!}$ ?

Then $4^{k+1}=4^k*4^1=4^k *4$

So how can you simplify $\frac{4^k}{4^{k+1}}$ ?