Hello,
Assuming that i read it correctly...
Hello, I am having trouble finding the indicated integral on these two problems.
{ (e^x/2 + x times square root of x) dx
and
{ x^1.1 (1/3x - 1) dx
For the first one, I had 1(1/2)e^x = 1/2e^x + (1/1+1) (1/(1/2)+1) which doesn't appear to be correct, I also can't figure out the second one. If someone could illustrate how these integrals are found, Thank you.
Well the way my professor said to do these, was to put the constants in front, (1/2)? and do 1 over p+1 times x^p+1 x^p dx = 1/p+1 X^p+1 So relating this back to this problem, we have x times the square root of x, so the x term would be (1/2)x^2 and the square root is (1/1.5)x^1.5 Is this correct? This still doesn't lead to 2/5x^5/2
This is what I am getting for the entire problem:
1/2e^x + (1/2x^2)(1/(3/2)x^3/2) When I differentiate each one to check my answer, they do in fact differentiate back to the original terms in the problem, so that is what is confusing me, Hope I have explained this well. I just looked closer at your work, and you added the exponents on the x terms, I was multiplying them, but they should be added right?
Thanks Moo, it was that small part that had me hung up. How would this problem be intergrated:
{ x^1.1 (1/3x -1) Would I do the same thing as we just did in the previous problem? I started doing it and got (1/2.1)x^2.1 I know the second term we will have the divide by zero error, so this goes to lnx if I am not mistaken? The last term would be (1/2)x^2 but this is all being multiplied...
Ok, so if I understand you correctly, it looks like you multiplied x^1.1 by 1/3x, giving us x^1.1 / 3x. The exponent on -1 is 1 so you subtracted it from the exponent 1.1 ? What happened to the denominator of 3 in these terms? I don't understand why x^.1 is subtracting x^1.1 Could you explain this?