you could see theOriginally Posted by nath_quam
where x=
now, 1- cosx is always greater than or equal to zero.
if 1- cosx is greater than zero., I is decreasing
I is stationary if cosx =1 i.e.
or
hence I is stationary at
Imagine the motion of the same particle.Originally Posted by Soroban
Let describes the motion of the particle. Consider the motion from to .Can we find at . In other words, if a function is defined on the closed interval [a,b], can it be differentiable on one of its end-points e.g.'a'?