What would be the limit? an = -5 + (-2/3)^n Also, for the sequence, 1/2,1/4,1/8 would the formula be 1/2^(n-1) And, 1/2,1/4,1/6 would the formula be 1/2^n ?
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Originally Posted by ch2kb0x What would be the limit? an = -5 + (-2/3)^n Also, for the sequence, 1/2,1/4,1/8 would the formula be 1/2^(n-1) And, 1/2,1/4,1/6 would the formula be 1/2^n ? $\displaystyle \lim_{n \to \infty}(-5+ \underbrace{\left( \frac{-2}{3}\right)^n)}_{r<1,r^n \to 0}=-5+0=-5$ The first is true if you start with n=2. The 2nd would be $\displaystyle a_n=\frac{1}{2n}$
Ohh ok, thanks Well what would the formula be if it started at 1/2 as stated.
Originally Posted by ch2kb0x Ohh ok, thanks Well what would the formula be if it started at 1/2 as stated. $\displaystyle a_n=\left( \frac{1}{2}\right)^n$ for n = 1
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