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Math Help - who can solve this question?!!

  1. #1
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    Question who can solve this question?!!

    The trajectory of a moving particle is given by, y = sin(x) . exp(.2x) .
    Then, the acceleration of the particle is:
    • cos(x)+4exp^(-2x)
    • -cos(x)+4exp^(-2x)
    • -sin(x)-2exp^(-2x)
    • sin(x)-2exp^(-2x)
    • NON of mentioned
    please who knows what is the answer
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by soso love View Post
    The trajectory of a moving particle is given by, y = sin(x) . exp(.2x) .

    Then, the acceleration of the particle is:

    • cos(x)+4exp^(-2x)
    • -cos(x)+4exp^(-2x)
    • -sin(x)-2exp^(-2x)
    • sin(x)-2exp^(-2x)
    • NON of mentioned

    please who knows what is the answer
    v(t)=2sin(x)e^{2x}+cos(x)e^{2x}\Rightarrow{x'(t)}...and then a(t)\Rightarrow{v'(t)}\Rightarrow{4sin(x)e^{2x}+2c  os(x)e^{2x}+2cos(x)e^{2x}-sin(x)e^{2x}}
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  3. #3
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    non

    SO the answer is
    NON mentioned right!!!?
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  4. #4
    Moo
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    Hello,

    Please confirm or infirm my doubts

    Is it sin(x)exp(-2x) or sin(x)-exp(-2x) or what ? What do the . refer to ?
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