The question goes this way:

The complex variable function f(z) is analytic in the complex plane, and |f(z)| < M, where M is a constant.(Q)

Prove that

I = ∫C f(z) / [(z-a)(z-b)] dz = 0,

where a, b are two different complex number, and C is the circle |z| = R, (R > |a|, R> |b|).

Let R→∞

Using residual theorem, I have only managed to reach this far:

I = 2πi {[f(a)-f(b)]/(a-b)}

Now, how do I prove that f(a)=f(b)?

Thanks.