$\displaystyle \int \frac {1} {xlnx} dx$ I tried doing it with substitution, parts, but neither would work.
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Originally Posted by tttcomrader $\displaystyle \int \frac {1} {xlnx} dx$ I tried doing it with substitution, parts, but neither would work. Substitute lnx =t. You you will get the answer lnt + c which in equivalent to ln(lnx) + c.
Ha, I was thinking about doing that, but I was thinking too hard. I keep thinking I could not seperate $\displaystyle \frac {1}{xlnx}$ into $\displaystyle \frac {1}{x}$ and $\displaystyle \frac {1}{lnx}$
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