I have the limits, -2< a < 0 and f(a) = -6a/a+1
As a varies between -2 and 0, what are the limits of f(a) ????
$\displaystyle f'(a)=\frac{-6(a+1)+6a}{(a+1)^2}$ using this find the zeros test them in the second derivative to check for their max or min status and then test the enpoints of the interval whichever yields the greates value for y when put into the original function is your max...i will be back later to explain more