Results 1 to 5 of 5

Math Help - Fundamental Theorum of Calculus: Evaluate Indefinate Integral

  1. #1
    Junior Member shepherdm1270's Avatar
    Joined
    Mar 2008
    Posts
    47

    Fundamental Theorum of Calculus: Evaluate Indefinate Integral

    = Integral from 1 to 4: 3/(2x+1)^2
    = Integral from 1 to 4: 3(2x+1)^-2

    now how do I find the anti-derivative of that so that I can find F(4)-F(1)??
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6
    Yop,

    Make appear the derivative of 2x+1

    Then, the antiderivative of u'(x) u^n(x) is \frac{u^{n+1} (x)}{n+1}

    Do you understand ? Or do you need me to show ?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member shepherdm1270's Avatar
    Joined
    Mar 2008
    Posts
    47
    i'm still not sure, would you mind showing me?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6
    3(2x+1)^{-2}=\frac{3}{2} \underbrace{2}_{u'(x)} \underbrace{(2x+1)}_{u(x)} \ ^{-2}

    So using the formula i gave you, the antiderivative will be :

    \frac{3}{2} \frac{u^{n+1} (x)}{n+1}=\frac{3}{2} \frac{(2x+1)^{\overbrace{-2+1}^{-1}}}{-2+1}=\frac{-3}{2(2x+1)}

    Is it better ?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member shepherdm1270's Avatar
    Joined
    Mar 2008
    Posts
    47
    infinately!! thanks so much!!!!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 8
    Last Post: November 29th 2010, 01:40 PM
  2. Replies: 3
    Last Post: April 22nd 2010, 06:25 PM
  3. Replies: 5
    Last Post: April 22nd 2010, 06:17 PM
  4. Replies: 3
    Last Post: December 15th 2009, 01:44 PM
  5. Fundamental Theorum of Integral
    Posted in the Calculus Forum
    Replies: 1
    Last Post: April 29th 2007, 02:16 PM

Search Tags


/mathhelpforum @mathhelpforum