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**DiscreteW** With my exam on Friday, I'm trying to get all these practice probs done since some of them will be on the exam.

If $\displaystyle P$ is the Parity Operator, determine the parity of the functions below:

$\displaystyle P\sin{x} = ?$

$\displaystyle Pe^{-x} = ?$

$\displaystyle P(e^{x} + e^{-x}) = ?$

Now, if $\displaystyle H$ is the Hamiltonian Operator with $\displaystyle V(-x) = V(x)$, find the parity of

$\displaystyle PHe^{-x} = ?$

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So for the first func, we know that sin(x) is an odd function, and hence that would be -sin(x) if I'm not mistaken since the parity would take sin(x) and make it sin(-x) and thus it'd have parity -1? We only dealt with cos/sin in our notes, so I'm not sure what an extra operator does and the role of exponential functions.