what is the first and second derivative of:
f(x) = (x^(2/3))(x-5)
for the first derivative i got f'(x) = (5/3)(x^(2/3)) - (10/3)(x^(-1/3))...... but i need to be able to get the critical numbers for this and i can't figure out what they are. I know i am suppose to set the equation equal to 0 but i still can't get it. And i have to show my work so I'm not suppose to use a calculator.
yes thank you...
Now i'm having trouble with the 2nd derivative... if i have f'(x) = (5/3)(x^(2/3)) - (10/3)(x^(-1/3))... then does the 2nd derivative f"(x) = (10/9)(x^(-1/3)) + (10/9)(x^(-4/3)) ???