Hello, I have the following expression I'd like to derive in terms of 'x'. 'k' is just a constant.
$\displaystyle
f(x) = 2(\frac{\sin{x}+1}{2})^k
$
I haven't done this sort of maths for a while, any pointers?
Hello,
$\displaystyle f(x)=2(u(x))^k$
The derivative of such a function is :
$\displaystyle f'(x)=2ku'(x)(u(x))^{k-1}$
$\displaystyle u(x)=\frac{\sin(x)+1}{2}=\frac{\sin(x)}{2}+\frac{1 }{2}$
So $\displaystyle u'(x)=\frac{\cos(x)}{2}$
And then substitute it in f'(x)