The normal to the curve represented by the equation y=x^2+6x+4 at the point (-2,-4) also intersects the curve at x= A) -6 B) -9/2 C) -7/2 D) -3 E)-1/2
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Originally Posted by andrewsx The normal to the curve represented by the equation y=x^2+6x+4 at the point (-2,-4) also intersects the curve at x= A) -6 B) -9/2 C) -7/2 D) -3 E)-1/2 Just use the equation of the normal line $\displaystyle y-x_0=\frac{-1}{f'(x_0)}\bigg(x-x_0\bigg)$
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