with the maclaurin series is the expansion or answer wateva to arsinh(4/3+x) = f(0)+(f'(0))/2! x (x)^2 + (f''(0))/3! x (x)^3.... or is it f(0)+(f'(0))/2! x (4/3+x)^2 + (f''(0))/3! x (4/3+x)^3.....???
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The latter. The Maclaurin series is given as: Here, you are dealing with with
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