# Math Help - maclaurin series quick Q

1. ## maclaurin series quick Q

with the maclaurin series is the expansion or answer wateva to arsinh(4/3+x)

= f(0)+(f'(0))/2! x (x)^2 + (f''(0))/3! x (x)^3....

or is it f(0)+(f'(0))/2! x (4/3+x)^2 + (f''(0))/3! x (4/3+x)^3.....???

2. The latter. The Maclaurin series is given as:

$f(x) = 1 + f'(0)x + \frac{f''(0)}{2!}x^{2} + \frac{f^{(3)}(0)}{3!}x^{3} + ...$

Here, you are dealing with $f\left(\frac{4}{3} + x\right)$ with $f(x) = sinh^{-1} x$