The curves y + ax^2 +b and y = 2x^2 +cx have a common tangent at the point (-1,0).

Find a, b and c.

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- June 13th 2006, 04:57 PMjayson81[SOLVED] Anyone know ?
The curves y + ax^2 +b and y = 2x^2 +cx have a common tangent at the point (-1,0).

Find a, b and c. - June 13th 2006, 06:03 PMThePerfectHackerQuote:

Originally Posted by**jayson81**

Substitute that into the second function,

Thus,

solve,

Thus, the second function has equation,

.

Since we say that these two function have a common tangent means the equation of the tangent through point (-1,0) is the same. Remember from analytic geomtery that two lines having same slope at same point are the same. Same thing here the tangent lines share a point thus they need to have the same slope.

The slope at for the first function is,

at is .

The slope for the second is,

at is

Thus, thus,

All we need is to find "b" in,

since (-1,0) is on the curve we have,

thus,

Thus,

Which is not true.

Thus, either you erred in the formulation of your question or there is no such numbers. - June 14th 2006, 05:08 AMSoroban
Hello, jayson81!

I got the same result as ThePerfectHacker, but I find that the solution works . . .

Quote:

The curves and have a common tangent at the point .

Find , and .

. .

. .

Since the slopes are equal at , we have:

. .

Since , we get: . . . and hence:

Therefore: .

The parabolas are: . and

They share the common point where they both have slope