Hello, yakkow!

Differentiate implicitly: .Find the normal to the curve that is parallel to the line

Factor: . . . . slope of thetangent

The slope of thenormalis: .

The line has slope

So we have: .

Substitute into the original equation:

. . .

The corresponding y-values are:

We seem to havetwonormals: one at (2,0), another at (0,2)

At (2,0) with slope -1, the equation of the normal is:

. . .

At (0,2) with slope -1, the equation of the normal is:

. . .

Ha!. . . It's the same line!