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Thread: find limit by rearrangement or L'Hopital's?

  1. April 12th 2008, 05:57 PM #16
    ThePerfectHacker
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    The best way to solve these types of problems falls under one general theorem here.
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  2. April 12th 2008, 10:05 PM #17
    Mathstud28
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    O I am sorry

    Quote Originally Posted by o_O View Post
    Sure you do.

    \left[ \left(1 + \frac{1}{n}\right)^{n}\right]^{3} = \left[ \left(1 + \frac{1}{n}\right)^{3}\right]^{n} = \left[ \left(1 + \frac{1}{n}\right) \cdot \left(1 + \frac{1}{n}\right) \cdot \left(1 + \frac{1}{n}\right)\right]^{n}
    I read one part and responded to a different one
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