Prove that d/dx (cosecx) = -cosecxcotx

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- June 13th 2006, 12:38 AMnath_quamDifferentiate cosecx
Prove that d/dx (cosecx) = -cosecxcotx

- June 13th 2006, 04:53 AMtopsquarkQuote:

Originally Posted by**nath_quam**

cscx = 1/sinx

-Dan - June 13th 2006, 05:13 AMCaptainBlack
What would you like us to do with the attachment?

RonL - June 13th 2006, 06:13 AMJameson
For part (a) integrate dI and then using your initial value solve for the constant of integration.

- June 13th 2006, 11:47 AMThePerfectHacker
Since,

Then, when you take its derivative apply quotient rule,

Then,

=

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For reference,

If is a diffrenciable function at and is a diffrenciable function at such as, , then is diffrenciable at and its derivative at is,

- June 13th 2006, 02:29 PMnath_quamQuotient Rule
Perfect Hacker shouldn't the quotient rule have a minus in the middle not a plus as you have it Thanks Nath and how would i go about doing the three parts of the attachment

- June 13th 2006, 02:53 PMThePerfectHackerQuote:

Originally Posted by**nath_quam**

Where do you see a plus?

(Okay I admit I edited my message, you are right)