How can you prove that any automorphism of $\displaystyle \mathbb{Q} (\sqrt[3]{2})$ leaves $\displaystyle \mathbb{Q}$ fixed?

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- Apr 10th 2008, 07:44 PMsyme.gabrielAutomorphisms of Q
How can you prove that any automorphism of $\displaystyle \mathbb{Q} (\sqrt[3]{2})$ leaves $\displaystyle \mathbb{Q}$ fixed?

- Apr 10th 2008, 08:03 PMThePerfectHacker