I'm still having a bit of trouble with the concept of the derivative of the exponential function (e^x).
"If h(z) = (z^2)(1+e^-z), determine h'(-1)."
How do I solve this?
this will be helpful $\displaystyle \frac{D[e^{u(x)}]}{dx}=e^{u(x)}\cdot{u'(x)}$...so for $\displaystyle e^{-x}$ we have $\displaystyle u(x)=-x,u'(x)=-1$....so using the formula I have you we have $\displaystyle \frac{D[e^{-x}]}{dx}=e^{-x}\cdot{-1}=-e^{-x}$ as indicated above