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Math Help - Delta Values

  1. #1
    Junior Member R3ap3r's Avatar
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    Delta Values

    I'm stuck on this particular problem. It's given me headaches just staring at it. Can anyone help me with this? Question is:
    To 2 decimal places, find the value of \Delta\;y and dy for the given values of \Delta\;x and dx.

    y = 2(x^2 - 3x)^2
    x = 4
    \Delta\;x = 0.1
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    Ok

    Quote Originally Posted by R3ap3r View Post
    I'm stuck on this particular problem. It's given me headaches just staring at it. Can anyone help me with this? Question is:
    To 2 decimal places, find the value of \Delta\;y and dy for the given values of \Delta\;x and dx.

    y = 2(x^2 - 3x)^2
    x = 4
    \Delta\;x = 0.1
    \Delta{y}\approx{f'(x)\cdot{\Delta{x}}}
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  3. #3
    Behold, the power of SARDINES!
    TheEmptySet's Avatar
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    Yuma, AZ, USA
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    Quote Originally Posted by R3ap3r View Post
    I'm stuck on this particular problem. It's given me headaches just staring at it. Can anyone help me with this? Question is:
    To 2 decimal places, find the value of \Delta\;y and dy for the given values of \Delta\;x and dx.

    y = 2(x^2 - 3x)^2
    x = 4
    \Delta\;x = 0.1
    Remember that
    \Delta x =dx

    The change in y is given by

    \Delta y =f(x+\Delta x) -f(x)=f(4.1)-f(4)=40.68-32=8.68

    y=f(x) \iff \frac{dy}{dx}=f'(x) \iff dy=f'(x)dx

    dy=f'(4)(0.1)=(80)(0.1)=8
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