The question goes this way:
Given the complex inverse sine function w(z)=sin-¹(z) is defined such that z=sin(w).
Writing sin(w) in terms of complex exponential function, show that:
arcsin(z) = - i log[ i z ± √(1-z²)]
Thanks in advance.
The question goes this way:
Given the complex inverse sine function w(z)=sin-¹(z) is defined such that z=sin(w).
Writing sin(w) in terms of complex exponential function, show that:
arcsin(z) = - i log[ i z ± √(1-z²)]
Thanks in advance.