Can anyone help me solve: the integral from 5 to infinity of: 7/((n^2)-16)
If you can just solve the integral that would be great! I can do the limit to infinity from there....I am having a lot of trouble with this one.
Thank you!!
$\displaystyle \int_{5}^{\infty} \frac{7}{n^{2} -16} dn = \int_{5}^{\infty} \frac{7}{(n-4)(n+4)} dn$
The trick is to split the expression into partial fractions, i.e.
$\displaystyle \frac{7}{(n-4)(n+4)} = \frac{A}{n-4} + \frac{B}{n + 4}$
Solve for A and B and the integral should be easier to evaluate.