1. ## Calculus

I need some help on this problem. A snowball is melting at the rate of $6.00\; \frac{cm^3}{min}$ If it remains spherical, how fast is the radius decreasing when the radius is $2.00\; cm$ ?

2. Originally Posted by Vitamin
I need some help on this problem. A snowball is melting at the rate of $6.00\; \frac{cm^3}{min}$ If it remains spherical, how fast is the radius decreasing when the radius is $2.00\; cm$ ?
the volume of a sphere is given by:

$V = \frac 43 \pi r^3$

differentiate implicitly with respect to t (time)

$\Rightarrow \frac {dV}{dt} = 4 \pi r^2 \frac {dr}{dt}$

you are given dV/dt (note that this is negative) and r, you want dr/dt, so solve for it

3. ## ok

Originally Posted by Vitamin
I need some help on this problem. A snowball is melting at the rate of $6.00\; \frac{cm^3}{min}$ If it remains spherical, how fast is the radius decreasing when the radius is $2.00\; cm$ ?
you are given that $\frac{dV}{dt}=-6$...now by using $V_{sphere}=\frac{4}{3}\pi{r^3}$...we have our equation...differntiating we get $\frac{dV}{dt}=4\pi{r^2}\cdot{dr}{dt}$...we know the values of $\frac{dV}{dt}$ and $r$ so plug and solve

4. ## Ahhh

Originally Posted by Jhevon
the volume of a sphere is given by:

$V = \frac 43 \pi r^3$

differentiate implicitly with respect to t (time)

$\Rightarrow \frac {dV}{dt} = 4 \pi r^2 \frac {dr}{dt}$

you are given dV/dt (note that this is negative) and r, you want dr/dt, so solve for it
Not this enter your answer $e^{.0321651651654}$ seconds before me thing again haha

5. Originally Posted by Mathstud28
Not this enter your answer $e^{.0321651651654}$ seconds before me thing again haha
that's right1 i can read your mind and tell which problem you are planning to answer next. so i just hurry up and answer it before you. Muhuhahahahahahahaha

6. ## Well....

Originally Posted by Jhevon
that's right1 i can read your mind and tell which problem you are planning to answer next. so i just hurry up and answer it before you. Muhuhahahahahahahaha
Haha its sad because I believe you