if we have the above, then how would the answer change if we changed d(v/x)/dx to: 1) d(2v/x)/dx 2) d(v^2/x)/dx 3) d((v+3)/x)/dx thanks
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few question before we start. Are you able to derive the original result ? does the quotient rule mean anything to you? Bobak
Originally Posted by Richyie if we have the above, then how would the answer change if we changed d(v/x)/dx to: 1) d(2v/x)/dx 2) d(v^2/x)/dx 3) d((v+3)/x)/dx thanks Just use this $\displaystyle \frac{D[\frac{u}{v}]}{dx}=\frac{v\frac{du}{dx}-u\frac{dv}{dx}}{v^2}$
then would this be right: d(v^2/x)/dx = ( 2vx(dv/dx) - v^2 ) / x^2 thnx
Originally Posted by Richyie then would this be right: d(v^2/x)/dx = ( 2vx(dv/dx) - v^2 ) / x^2 thnx $\displaystyle \frac{D[\frac{v^2}{x}]}{dx}=\frac{x\cdot{2}\cdot{v}\cdot\frac{dv}{dx}-v^2}{x^2}$
Originally Posted by Mathstud28 $\displaystyle \frac{D[\frac{v^2}{x}]}{dx}=\frac{x\cdot{2}\cdot{v}\cdot\frac{dv}{dx}-v^2}{x^2}$ Just as a disclaimer...this answer is valid if $\displaystyle v(x)$ is what $\displaystyle v$ implied and not a constant
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