we have
dv/dx = v-x^2+1 / x
then how do we deduce from that:
d(v/x)/dx = -1 + 1/x^2 ? ?
thanks
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we have
dv/dx = v-x^2+1 / x
then how do we deduce from that:
d(v/x)/dx = -1 + 1/x^2 ? ?
thanks
Please use parenthesis!!Quote:
Originally Posted by Richyie
$\displaystyle \frac{d}{dx} \left ( \frac{v}{x} \right ) = \frac{\frac{dv}{dx} x - v}{x^2}$
$\displaystyle = \frac{(v - x^2 + 1) - v}{x^2} = \frac{-x^2 + 1}{x^2} = -1 + \frac{1}{x^2}$
For the record:
v-x^2+1 / x is
$\displaystyle v - x^2 + \frac{1}{x}$
-Dan
yep i meant (v-x^2+1) / x sorry
thanks :)
