I am 100% sure but just to make sure...I was just messing around and I just wondered if this is right $\displaystyle 3^{x}=\sum_{n=0}^{\infty}\frac{[\ln(3)]^{n}x^n}{n!},\forall{x}\in\mathbb{R}$ right?
I am 100% sure but just to make sure...I was just messing around and I just wondered if this is right $\displaystyle 3^{x}=\sum_{n=0}^{\infty}\frac{[\ln(3)]^{n}x^n}{n!},\forall{x}\in\mathbb{R}$ right?
$\displaystyle 3^x=e^{x \ln(3)}$, so trivialy yes.