1. ## differencial equation

Find all values of k for which the function y=sin(kt) satisfies the differential equation y"+10y=0. Separate your answers by commas.

thanks for any help.

2. Hello,

y'=k*cos(kt)

y''=-k²*sin(kt)

y''+10y=0 <=> -k²*sin(kt)+10sin(kt)=0 <=> 10=k² <=> $k=\{\sqrt{10},-\sqrt{10}\}$

3. the answers provided didn't seem to work. thanks for the help

4. Well, k=0 is also a solution, as y will be equal to 0.

5. awsome, that helped me out (I'm working on the same stuff with waite)

6. that was it. they were right thanks a lot for the help