Find all values of k for which the function y=sin(kt) satisfies the differential equation y"+10y=0. Separate your answers by commas. thanks for any help.
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Hello, y'=k*cos(kt) y''=-kČ*sin(kt) y''+10y=0 <=> -kČ*sin(kt)+10sin(kt)=0 <=> 10=kČ <=> $\displaystyle k=\{\sqrt{10},-\sqrt{10}\}$
the answers provided didn't seem to work. thanks for the help
Well, k=0 is also a solution, as y will be equal to 0.
awsome, that helped me out (I'm working on the same stuff with waite)
that was it. they were right thanks a lot for the help
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