Hello,
y=ce^-2+e^-x
I guess it's -2x
So
This is really awful !
i cant seem to figure this out
It is easy to check that for any value of c, the function y=ce^-2+e^-x
is solution of equation y'+2y=e^-x
Find the value of c for which the solution satisfies the initial condition y(-4)=10
c=?
thanks for any help