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Math Help - im having trouble with this one.

  1. #1
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    im having trouble with this one.

    i cant seem to figure this out

    It is easy to check that for any value of c, the function y=ce^-2+e^-x
    is solution of equation y'+2y=e^-x
    Find the value of c for which the solution satisfies the initial condition y(-4)=10
    c=?

    thanks for any help
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  2. #2
    Moo
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    Hello,

    y=ce^-2+e^-x

    I guess it's -2x

    So y(x)=c*e^{-2x}+e^{-x}

    y(-4)=10 \leftarrow 10=c*e^8+e^4

    c*e^8=10-e^4

    c=\frac{10-e^4}{e^8}

    This is really awful !
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  3. #3
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    that worked your on fire! thanks a lot.
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