Thread: im having trouble with this one.

i cant seem to figure this out

It is easy to check that for any value of c, the function y=ce^-2+e^-x
is solution of equation y'+2y=e^-x
Find the value of c for which the solution satisfies the initial condition y(-4)=10
c=?

thanks for any help

Hello,

y=ce^-2+e^-x

I guess it's -2x

So







This is really awful !

that worked your on fire! thanks a lot.