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Math Help - Indefinite Intergral - 1 question - Please Help

  1. #1
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    Indefinite Intergral - 1 question - Please Help

     \int( \sqrt[3]{u} + \cos2u + e^{-u} )du

    e = Exponential
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  2. #2
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    Quote Originally Posted by ForgottenMemorie View Post
     \int( \sqrt[3]{u} + \cos2u + e^{-u} )du

    e = Exponential
    Some reminders:
    \int \sqrt[3]{u}~du = \int u^{1/3}~du
    Use the power rule for integration.

    \int cos(2u)~du
    Use the substitution x = 2u. Then you need to know
    \int cos(x)~dx = sin(x) + C.
    (This is not the answer. There's a multiplicative factor too.)

    \int e^u~du = e^u + C
    Let x = -u. Then you need to know
    \int e^x~dx = e^x + C

    -Dan
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    \int u^{1/3} \sin2u e^{-x}

    It that the answer>?
    Last edited by ForgottenMemorie; April 8th 2008 at 04:12 AM.
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    That was not a new question, that was a typo, i was hving trouble typing what i wanted in.
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by ForgottenMemorie View Post
    \int u^{1/3} \sin2u e^{-x}

    It that the answer>?
    How could that possibly be the answer? You are adding the terms in the integrand, so you wouldn't multiply. And I presume that your question is asking you to integrate, so do the integrals.

    Or is the question actually to integrate
    \int u^{1/3}~sin(2u)~e^u~du

    -Dan
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