At time t, the position of a particle moving on a curve is given by
(a) Find the exact value of t at which the curve has a horizontal tangent.
(b) Find dy/dx in terms of t.
dy/dx = (6exp(2t)-2exp(-2t))/(2exp(2t)+2exp(-2t))
(c) Find .
ok so i was able to find dy/dx, but i need help with the rest...thanks...